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| 产地 | 中国 |
| 品牌 | Chemstan |
| 货号 | LC-01 |
| 用途 | 中间体 |
| 包装规格 | 20mg |
| 纯度 | 98%% |
| CAS编号 | 1210344-57-2 |
| 是否进口 | 否 |
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Fields of Application :
PF-04971729 is a potent and selective inhibitor of the sodium-dependent glucose cotransporter 2, is currently in phase 2 trials for the treatment of diabetes mellitus.
| CAS Number: | 1210344-57-2 |
| Purity: | >98% |
| Molecular Weight: | 436.9 |
| Molecular Formula: | C22H25ClO7 |
Quality Control: HPLC、NMR、 LC/MS(Please contact us to get the QC report)
| Synonyms: | PF04971729,PF 04971729 (Ertugliflozin) |
| Chemical Name: | |
| Storage: | 2 years -20°C Powder, 2 weeks4°C in DMSO,6 months-80°C in DMSO |
Note: Products for research use only, not for human use
Description:
PF-04971729, a potent and selective inhibitor of the sodium-dependent glucose cotransporter 2, is currently in phase 2 trials For the treatment of diabetes mellitus. Inhibitory effects against the organic cation transporter 2-mediated uptake of [14C]met Formin by PF-04971729 also were very weak (IC50 900μM).The disposition of PF-04971729, an orally active selective inhibitor of the sodium-dependent glucose cotransporter 2, was studied after a single 25-mg oral dose of [14C]-PF-04971729 to healthy human subjects. The absorption of PF-04971729 in humans was rapid with a Tmax at ~ 1.0 h. Of the total radioactivity excreted in feces and urine, unchanged PF-04971729 collectively accounted For ~ 35.3% of the dose, suggestive of moderate metabolic elimination in humans. For the detailed information about the solubility of PF-04971729 (Ertugliflozin) in water, the solubility of PF-04971729 (Ertugliflozin) in DMSO, the solubility of PF-04971729 (Ertugliflozin) in PBS buffer, the animal experiment（test） of PF-04971729 (Ertugliflozin),the in vivo,in vitro and clinical trial test of PF-04971729 (Ertugliflozin),the cell experiment（test） of PF-04971729 (Ertugliflozin),the IC50, EC50 and Affinity of PF-04971729 (Ertugliflozin).
References:
C1=CC([C@@]23O[C@@](CO)(CO2)[C@H](O)[C@@H](O)[C@@H]3O)=CC(CC2=CC=C(OCC)C=C2)=C1Cl
